AMC 8 L2: Basic Geometry

Complete problem set with solutions and individual problem pages

Problem 1 Easy

Answer the following questions:

Answer:
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Problem 2 Easy

As shown in the figure below, the correct expression to calculate the area of the trapezoid is            .

  • A.

    \left( 12+26 \right)\times 12

  • B.

    \left( 12+26 \right)\times 15\div 2

  • C.

    \left( 12+26 \right)\times 13\div 2

  • D.

    \left( 12+26 \right)\times 12\div 2

Answer:D

N/A

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Problem 3 Medium

Four friends, Art, Roger, Paul and Trisha, bake cookies, and all cookies have the same thickness. The shapes of the cookies differ, as shown.

\bigcirc Art’s cookies are trapezoids:

\bigcirc Roger’s cookies are rectangles:

\bigcirc Paul’s cookies are parallelograms:

\bigcircTrisha’s cookies are triangles:

Each friend uses the same amount of dough, and Art makes exactly 12 cookies.

(2003 AMC8 Problem, Question #8, #9, #10)

Answer:
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Problem 4 Easy

Rectangle ABCD and right triangle DCE have the same area. They are joined to form a trapezoid, as shown. What is CE? (2014 AMC8 Problem, Question #14)

  • A.

    12

  • B.

    13

  • C.

    14

  • D.

    15

  • E.

    16

Answer:A

5\times6 \times 2\div 5=12

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Problem 5 Easy

Three identical rectangles are put together to form rectangle ABCD, as shown in the figure below. Given that the length of the shorter side of each of the smaller rectangles is 5 feet, what is the area in square feet of rectangle ABCD? (2019 AMC8 Problem, Question #2)

  • A.

    45

  • B.

    75

  • C.

    100

  • D.

    125

  • E.

    150

Answer:E

5\times10\times3=150

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Problem 6 Easy

Points A, B, C and D are midpoints of the sides of the larger square. If the larger square has area 60, what is the area of the smaller square? (2006 AMC8 Problem, Question #05)

  • A.

    15

  • B.

    20

  • C.

    24

  • D.

    30

  • E.

    40

Answer:D

Solution 1: Drawing segements AC and BD, the number of triangles outside square ABCD is the same as the number of triangles inside the square. Thus areas must be equal so the area of ABCD is half the area of the larger square which is \frac{60}{2}=\text{D} 30.

Solution 2: If the side length of the larger square is x, the area of the smaller square is \frac{{{x}^{2}}}{2}.

Thus, the area of the smaller square in the picture is \frac{60}{2}=\text{D} 30.

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Problem 7 Easy

Figure ABCD is a square. Inside this square three smaller squares are drawn with the side lengths as labeled. The area of the shaded L-shaped region is            . (2000 AMC8 Problem, Question #6)

  • A.

    7

  • B.

    10

  • C.

    12.5

  • D.

    14

  • E.

    15

Answer:A

Solution 1: 3\times1+3\times1+1\times1=7

Solution 2: 4\times4-3\times3=7

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Problem 8 Medium

Which of the following polygons has the largest area? (2002 AMC8 Problem, Question #15)

  • A.

    A

  • B.

    B

  • C.

    C

  • D.

    D

  • E.

    E

Answer:E

Each polygon can be partitioned into unit squares and right triangles with sidelength 1. Count the number of boxes enclosed by each polygon, with the unit square being 1, and the triangle being being .5. A has 5, B has 5, C has 5, D has 4.5, and E has 5.5. Therefore, the polygon with the largest area is E.

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Problem 9 Easy

The twelve-sided figure shown has been drawn on 1\text{cm}\times 1\text{cm} graph paper. What is the area of the figure in \text{c}{{\text{m}}^{2}}? (2018 AMC8 Problem, Question #4)

  • A.

    12

  • B.

    12.5

  • C.

    13

  • D.

    13.5

  • E.

    14

Answer:C

We count 3\times3=9 unit squares in the middle, and 4 small triangles each with an area of 1. Thus the answer is 9+4=13.

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Problem 10 Easy

What is the area enclosed by the geoboard quadrilateral below? (2004 AMC8 Problem, Question #14)

  • A.

    15

  • B.

    18\frac{1}{2}

  • C.

    22\frac{1}{2}

  • D.

    27

  • E.

    41

Answer:C

Solution 1:

S=100-S_1-S_2-S_3-S_4

=100-\frac{(5+6)\times3}{2}-\frac{6\times7}{2}-\frac{5\times4}{2}-\frac{6\times10}{2}

=22.5

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Problem 11 Easy

What is the area enclosed by the triangle below?

  • A.

    9

  • B.

    10

  • C.

    11

  • D.

    12

  • E.

    13

Answer:B

Solution 1: 24-8-3-3=10

Solution 2: (5\times3+5\times1)\div2=10

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Problem 12 Easy

Find the perimeter of the figure below.

  • A.

    18 m

  • B.

    20 m

  • C.

    28 m

  • D.

    36 m

Answer:D

(10+8)\times2=36 m

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Problem 13 Medium

In the diagram, all angles are right angles and the lengths of the sides are given in centimeters. Note the diagram is not drawn to scale. What is X, in centimeters? (2012 AMC8 Problem, Question #5)

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

  • E.

    5

Answer:E

The figure is the same height on both sides, so the sum of the lengths contributing to the height on the left side will equal the sum of the lengths contributing to the height on the right side.

1+1+1+2+X=1+2+1+6,

5+X=10,

X=5.

Thus, the answer is \text{E}.

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Problem 14 Easy

The letter T is formed by placing two 2\times4 inch rectangles next to each other, as shown. What is the perimeter of the T, in inches? (2006 AMC8 Problem, Question #6)

  • A.

    12

  • B.

    16

  • C.

    20

  • D.

    22

  • E.

    24

Answer:C

If the two rectangles were separate, the perimeter would be 2\times(2\times(2+4))=24. It easy to see that their connection erases 2 from each of the rectangles, so the final perimeter is 24-2\times2=20.

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Problem 15 Easy

The area of the shaded region BEDC in parallelogram ABCD is            .

  • A.

    24

  • B.

    48

  • C.

    60

  • D.

    64

  • E.

    80

Answer:D

S=(6+10)\times8 \div2=64

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Problem 16 Easy

In trapezoid ABCD, AD is perpendicular to DC, AD=AB=3, and DC=6. In addition, E is on DC, and BE is parallel to AD. Find the area of \triangle BEC. (2007 AMC8 Problem, Question #8)

  • A.

    3

  • B.

    4.5

  • C.

    6

  • D.

    9

  • E.

    18

Answer:B

3\times3\div2=4.5

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Problem 17 Easy

The cat shown has been drawn on 1\times1 graph paper. What is the area of the figure in cm^2?

  • A.

    10

  • B.

    11

  • C.

    12

  • D.

    13

Answer:B

N/A

Link Problem
Problem 18 Easy

Find the perimeter of the figure below.

  • A.

    110

  • B.

    120

  • C.

    200

  • D.

    220

Answer:D

50+50+10+10+50+50=220

Link Problem
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