2022 AMC 10 B

Complete problem set with solutions and individual problem pages

Problem 18 Easy

Consider systems of three linear equations with unknowns x, y, and z

a_{1}x+b_{1}y+c_{1}z=0

a_{2}x+b_{2}y+c_{2}z=0

a_{3}x+b_{3}y+c_{3}z=0

where each of the coefficients is either 0 or 1 and the system has a solution other than x=y=z=0. For example, one such system is \left\{ 1x+1y+0z=0,\ 0x+1y+1z=0,0x+0y+0z=0\right\} with a nonzero solution of  \left\{ x,y,z=\left\{ 1,-1,1\right\}\right\}. How many such systems are there?(The equations in a system need not be distinct, and two systems containing the same equations in a different order are considered different.)

  • A.

    302

  • B.

    338

  • C.

    340

  • D.

    343

  • E.

    344

Answer:B

The sufficient and necessary condition for a homogeneous linear system of equations to have a non-zero solution is that the rank of its coefficient matrix is less than the number of unknowns. In simple terms, it means that among these three equations, at least one must be "redundant" and cannot provide additional constraints to solve the equation. It is an identity that always holds true. Then we can discuss the following cases:

1^\circ One of the equations has coefficients that are all zeros. For each ordered triple of coefficients in the equations P_i=(a_i,b_i,c_i),i=1,2,3, there are a total of 2^3=8 choices. So for this case, we have 8^3-(8-1)^3=169 choices.

2^\circ None of the equations has coefficients that are all zeros and one of the equations can be obtained by linearly combining the other two equations (without loss of generality, we consider only addition).

1' Among the three equations, there are two equations that are identical. For this case, we have 7^3-7\cdot 6\cdot 5=133 choices.

2' In the equation that is a "sum", only two coefficients are 1 and the other one is 0. For example, for the ordered triples of coefficients in the equations we have (1,0,0)+(0,1,0)=(1,1,0). For this case, we have _3C_1\cdot _3P_3=18 choices.

3' In the equation that is a "sum", all of the three coefficients are 1. For example, for the ordered triples of coefficients in the equations we have (1,1,0)+(0,0,1)=(1,1,1). For this case, we have _3C_1\cdot _3P_3=18 choices.

So in total, we have 169+133+18+18=338 choices.