2015 AMC 8

Complete problem set with solutions and individual problem pages

Problem 13 Medium

How many subsets of two elements can be removed from the set \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11\} so that the mean (average) of the remaining numbers is 6?

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    5

  • E.

    6

Answer:D

Solution 1

Since there will be 9 elements after removal, and their mean is 6, we know their sum is 54. We also know that the sum of the set pre-removal is 66. Thus, the sum of the 2 elements removed is 66-54=12. There are only \boxed{\textbf{(D)}~5} subsets of 2 elements that sum to 12: \{1,11\}, \{2,10\}, \{3, 9\}, \{4, 8\}, \{5, 7\}.

 

Solution 2

We can simply remove 5 subsets of 2 numbers while leaving only 6 behind. The average of this one-number set is still 6, so the answer is \boxed{\textbf{(D)}~5}.