2017 AMC 10 A

Complete problem set with solutions and individual problem pages

Problem 12 Easy

Let S be a set of points (x, y) in the coordinate plane such that two of the three quantities 3, x+2, and y-4 are equal and the third of the three quantities is no greater than this common value. Which of the following is a correct description for S? (2017 AMC 10A Problem, Question#12)

  • A.

    a single point

  • B.

    two intersecting lines

  • C.

    three lines whose pairwise intersections are three distinct points

  • D.

    a triangle

  • E.

    three rays with a common endpoint

Answer:E

If the two equal values are 3 and x+2, then x=1. Also, y -4 ≤3 because 3 is the common value. Solving for y, we get y≤7.Therefore the portion of the line x=1 where y≤7 is part of S. This is a ray with an endpoint of (1, 7).

Similar to the process above, we assume that the two equal values are 3 and y-4. Solving the equation 3 = y - 4 then y=7. Also, x+2≤3 because 3 is the common value. Solving for x, we get x≤1. Therefore the portion of the line y=7 where x≤1 is also part of S. This is another ray with the same endpoint as the above ray: (1,7).

If x+2 andy-4 are the two equal values, then x+2 =y-4. Solving the equation for y, we get y= x+6. Also 3≤y-4 because y-4 is one way to express the common value. Solving for y, we get y≥7. Therefore the portion of the line y = x+6 where y≥7 is part of S like the other two rays. The lowest possible value that can be achieved is also (1, 7).

Since S is made up of three rays with common endpoint (1,7), the answer is

(\rm E) three rays with a common endpoint