AMC 8 Daily Practice Round 7

Complete problem set with solutions and individual problem pages

Problem 2 Easy

A large rectangle is divided into four pieces. Given that the perimeter of piece A is 8 cm, the perimeter of piece B is 30 cm, and the perimeter of piece D is 38 cm, what is the perimeter of the large rectangle?

  • A.

    42cm

  • B.

    44cm

  • C.

    46cm

  • D.

    48cm

  • E.

    50cm

Answer:C

Using the translation method, we know that:

The perimeter of the large rectangle = the perimeter of piece A + the perimeter of piece D, which is 8 + 38 = 46 cm.

Final answer: \boxed{46cm}.

Related Problems
Problem 1 AMC 8 Daily Practice Round 7
Problem 3 AMC 8 Daily Practice Round 7
Problem 4 AMC 8 Daily Practice Round 7
Problem 5 AMC 8 Daily Practice Round 7
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