2021 AMC 10 A Fall

Complete problem set with solutions and individual problem pages

Problem 6 Easy

Elmer the emu takes 44 equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in 12 equal leaps. The telephone poles are evenly spaced, and the 41 st pole along this road is exactly one mile (5280 feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?(2021 AMC Fall 10A, Question #6)

  • A.

    6

  • B.

    8

  • C.

    10

  • D.

    11

  • E.

    15

Answer:B

There are 41-1=40 gaps between the 41 telephone poles, so the distance of each gap is 5280 \div 40=132 feet. Each of Oscar's leaps covers 132 \div 12=11 feet, and each of Elmer's strides covers 132 \div 44=3 feet Therefore, Oscar's leap is 11-3=\mathbf{( B )} 8 feet longer than Elmer's stride.

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