2022 AMC 10 A

Complete problem set with solutions and individual problem pages

Problem 3 Easy

The sum of three numbers is 96. The first number is 6 times the third number, and the third number is 40 less than the second number. What is the absolute value of the difference between the first and second numbers?

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

  • E.

    5

Answer:E

Assume x is the third number.

6x+(x+40)+x=96

x=7

(x+40)-6x=5

Related Problems
Problem 1 2022 AMC 10 A
Problem 2 2022 AMC 10 A
Problem 4 2022 AMC 10 A
Problem 5 2022 AMC 10 A
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