2017 AMC 10 A

Complete problem set with solutions and individual problem pages

Problem 8 Easy

At a gathering of 30 people, there are 20 people who all know each other and 10 people who know no one. People who know each other hug, and people who do not know each other shake hands. How many handshakes occur? (2017 AMC 10A Problem, Question#8)

  • A.

    240

  • B.

    245

  • C.

    290

  • D.

    480

  • E.

    490

Answer:B

Each one of the ten people has to shake hands with all the 20 other people they don't know. So 10\cdot20 = 200. From there, we calculate how many handshakes occurred between the people who don't know each other. This is simply counting how many ways to choose two people to shake hands, or \left( \begin{matrix}10\\2\end{matrix}\right)=45. Thus the answer is 200+45= (\rm B)245.

We can also use complementary counting. First of all, \left( \begin{matrix}30\\2\end{matrix}\right)=435 handshakes or hugs occur. Then, if we can find the number of hugs, then we can subtract it from 435 to find the handshakes. Hugs only happen between the 20 people who know each other, so there are \left( \begin{matrix}20\\2\end{matrix}\right)=190 hugs. 435-190= (\rm B)245.

We can focus on how many handshakes the 10 people get.

The 1 \rm st person gets 29 handshakes.

2\rm nd gets 28.

\ldots\ldots

And the 10 \rm th receives 20 handshakes.

We can write this as the sum of an arithmetic sequence.

\dfrac{10(20+29)}{2} \Rightarrow 5(49) \Rightarrow 245. Therefore, the answer is (\rm B) 245.