2016 AMC 8

Complete problem set with solutions and individual problem pages

Problem 13 Medium

Two different numbers are randomly selected from the set \{ - 2, -1, 0, 3, 4, 5\} and multiplied together. What is the probability that the product is 0?

  • A.

    \frac16

  • B.

    \frac15

  • C.

    \frac14

  • D.

    \frac13

  • E.

    \frac12

Answer:D

Solution 1

1. Identify the total number of ways to select two different numbers from the set:

The set has 6 elements. The number of ways to choose 2 different numbers from 6 is given by the combination formula: \binom{6}{2} = \frac{6 \times 5}{2 \times 1} = 15.

2. Identify the favorable outcomes:

For the product to be zero, one of the chosen numbers must be zero. The set contains one zero (0). To have a product of zero, we need to choose 0 and any other number from the remaining five numbers -2, -1, 3, 4, 5.

The number of ways to choose 0 and one other number from the remaining five is 5.

3. Calculate the probability:

The probability is the number of favorable outcomes divided by the total number of outcomes: \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{5}{15} = \frac{1}{3}.

Thus, the probability that the product is 0 is \boxed{\textbf{(D)} \ \frac{1}{3}}.

 

Solution 2 

Because the only way the product of the two numbers is 0 is if one of the numbers we choose is 0, we calculate the probability of NOT choosing a 0. We get \frac{5}{6} \cdot \frac{4}{5} = \frac{2}{3}. Therefore our answer is 1 - \frac{2}{3} = \boxed{\textbf{(D)} \ \frac{1}{3}}.