2022 AMC 8

Complete problem set with solutions and individual problem pages

Problem 17 Hard

If n is an even positive integer, the double factorial notation n!! represents the product of all the even integers from 2 to n. For example, 8!! = 2 \cdot 4 \cdot 6 \cdot 8. What is the units digit of the following sum?2!! + 4!! + 6!! + \cdots + 2018!! + 2020!! + 2022!!

  • A.

    0

  • B.

    2

  • C.

    4

  • D.

    6

  • E.

    8

Answer:B

Solution 1

Notice that once n>8, the units digit of n!! will be 0 because there will be a factor of 10. Thus, we only need to calculate the units digit of

2!!+4!!+6!!+8!! = 2+8+48+48\cdot8.

We only care about units digits, so we have 2+8+8+8\cdot8, which has the same units digit as 2+8+8+4. The answer is \boxed{\textbf{(B) } 2}.

 

Solution 2 (Solution 1 worded differently)

We can see that after 8!! in the sequence, the units digit is always 0 (every value after 8!! is a multiple of 10). Therefore, our answer is the sum of the units digits of 2!!, 4!!, 6!!, and 8!! respectively. This sum is equal to 2 + 8 + 8 + 4, or \boxed{\textbf{(B) } 2}.