2024 AMC 8

Complete problem set with solutions and individual problem pages

Problem 8 Easy

On Monday, Taye has $2. Every day, he either gains $3 or doubles the amount of money he had on the previous day. How many different dollar amounts could Taye have on Thursday, 3 days later?

  • A.

    3

  • B.

    4

  • C.

    5

  • D.

    6

  • E.

    7

Answer:D

Solution 1

How many dollar values could be on the first day? Only 2 dollars. The second day, you can either add 3 dollars, or double, so you can have 5 dollars, or 4. For each of these values, you have 2 values for each. For 5 dollars, you have 10 dollars or 8, and for 4 dollars, you have 8 dollars or 7 dollars. Now, you have 2 values for each of these. For 10 dollars, you have 13 dollars or 20, for 8 dollars, you have 16 dollars or 11, for 8 dollars, you have 16 dollars or 11, and for 7 dollars, you have 14 dollars or 10.

On the final day, there are 11, 11, 16, and 16 repeating, leaving you with 8-2 = \boxed{\textbf{(D) 6}} different values.

 

Solution 2

Continue as in Solution 1 to get 7, 8, or 10 dollars by the 2nd day. The only way to get the same dollar amount occurring twice by branching (multiply by 2 or adding 3) from here is if 7+3=10\cdot 2 or 7+3=8\cdot 2 which both aren't true. Hence our answer is 3\cdot2=\boxed{\textbf{(D) 6}}.