2024 AMC 8

Complete problem set with solutions and individual problem pages

Problem 7 Easy

A 3 \times 7 rectangle is covered without overlap by 3 shapes of tiles: 2 \times 2, 1\times4, and 1\times1, shown below. What is the minimum possible number of 1\times1 tiles used?

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

  • E.

    5

Answer:E

Solution 1

We can eliminate B, C, and D, because they are not 21 subtracted by any multiple of 4. Finally, we see that there is no way to have A, so the solution is \boxed{\textbf{(E) 5}}.

 

Solution 2

Let x be the number of 1 by 1 tiles. There are 21 squares and each 2 by 2 or 1 by 4 tile takes up 4 squares, so x \equiv 1 \pmod{4}, so it is either 1 or 5. Color the columns, starting with red, then blue, and alternating colors, ending with a red column. There are 12 red squares and 9 blue squares, but each 2 by 2 and 1 by 4 shape takes up an equal number of blue and red squares, so there must be 3 more 1 by 1 tiles on red squares than on blue squares, which is impossible if there is just one, so the answer is \boxed{\textbf{(E) 5}}, which can easily be confirmed to work.