2018 AMC 10 A

Complete problem set with solutions and individual problem pages

Problem 2 Easy

Liliane has 50\% more soda than Jacqueline, and Alice has 25\% more soda than Jacqueline. What is the relationship between the amounts of soda that Liliane and Alice have?(2018 AMC 10A Problem, Question#2)

  • A.

    Liliane has 20\% more soda than Alice.

  • B.

    Liliane has 25\% more soda than Alice.

  • C.

    Liliane has 45\% more soda than Alice.

  • D.

    Liliane has 75\% more soda than Alice.

  • E.

    Liliane has 100\% more soda than Alice.

Answer:A

Let's assume that Jacqueline has 1 gallon(s) of soda. Then Alice has 1.25 gallons and Liliane has 1.5 gallons. Doing division, we find out that \frac{1.5}{1.25}=1.2, which means that Liliane has 20\% more soda. Therefore, the answer is \boxed{(\rm A)20\%}.

If Jacqueline has x gallons of soda, Alice has 1.25x gallons, and Liliane has 1.5x gallons. Thus, the answer is \frac{1.5}{1.25}=1.2, Liliane has 20\% more soda. Our answer is \boxed{(\rm A)20\%}.

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