AMC 8 Daily Practice Round 6

Complete problem set with solutions and individual problem pages

Problem 27 Easy

What is the value of 9999^2 + 19999

  • A.

    100000000

  • B.

    19999998

  • C.

    9999

  • D.

    199999999

  • E.

    99999999

Answer:A

9999^2 + 19999 = 9999^2 + 9999 \times 2 + 1= 9999^2 + 2 \times 9999 \times 1 + 1^2= (9999 + 1)^2 = 10000^2= 100000000

Final result:  \boxed{100000000}