AMC 10 Daily Practice Round 1

Complete problem set with solutions and individual problem pages

Problem 25 Easy

Five volunteers are randomly assigned to three different Olympic venues for reception work. What is the probability that each venue has at least one volunteer?

  • A.

    \frac{3}{5}

  • B.

    \frac{1}{15}

  • C.

    \frac{5}{8}

  • D.

    \frac{50}{81}

  • E.

    \frac{3}{20}

Answer:D

There are 3^5 = 243 ways to randomly assign 5 volunteers to 3 different Olympic venues.

To ensure that each venue has at least one volunteer, we consider two possible cases:

Case 1: One venue gets 3 volunteers, while the other two venues each get 1 volunteer.

Select which venue gets 3 volunteers: _3C_1.

Select which 3 volunteers go to that venue: _5C_1

Assign the remaining 2 volunteers to the remaining 2 venues: _2A_2

Total ways for this case: _3C_1 \times _5C_3 \times _2A_2 = 3 \times 10 \times 2 = 60.

Case 2: One venue gets 1 volunteer, while the other two venues each get 2 volunteers.

Select which venue gets 1 volunteer: _3C_1

Select which volunteer goes to that venue: _5C_1

Select 2 out of the remaining 4 volunteers for the second venue: _4C_2

The last 2 volunteers automatically go to the remaining venue.

Total ways for this case:

_3C_1 \times _5C_1 \times _4C_2 = 3 \times 5 \times 6 = 90.

The total number of favorable assignments is: 60 + 90 = 150.

Thus, the probability that each venue receives at least one volunteer is:

P = \frac{150}{243} = \frac{50}{81}.

Choose \boxed{D:\frac{50}{81}}.