AMC 8 Daily Practice Round 8

Complete problem set with solutions and individual problem pages

Problem 17 Hard

A car travels from City A to City B. If its speed is increased by 20\%, it can arrive one hour earlier than the originally planned time. If it travels 120 kilometers at the original speed and then increases its speed by 25\%, it can arrive 40 minutes earlier. What is the distance between City A and City B in kilometers?

  • A.

    260

  • B.

    270

  • C.

    280

  • D.

    290

  • E.

    300

Answer:B

When the car’s speed is increased by 20\%, the speed ratio is 5:6.

For the same distance, the time ratio should be 6:5.

Thus, the time to travel the whole distance at the original planned speed is 1 \div (6 - 5) \times 6 = 6 \ \text{hours}.

For the latter part of the trip, when the speed is increased by 25\%, the speed ratio is 4:5, so the time ratio should be 5:4.

Arriving 40 minutes earlier means that at the original planned speed, this part of the trip would take 40 \times 5 = 200 \ \text{minutes} = 3\frac{1}{3} \ \text{hours}.

From this, it is easy to find that the distance between A and B is 120 \div \left( 6 - 3\frac{1}{3} \right) \times 6 = 270 \ \text{km}.