AMC 8 Daily Practice - Area Tricks

Complete problem set with solutions and individual problem pages

Problem 4 Easy

Rectangle ABCD has a length of 8 centimeters and a width of 4 centimeters. Its diagonals AC and BD divide it into four parts, and diagonal AC is further divided into four equal segments. What is the area of the shaded part?

  • A.

    6cm^{2}

  • B.

    7cm^{2}

  • C.

    8cm^{2}

  • D.

    9cm^{2}

  • E.

    10cm^{2}

Answer:C

According to the formula for the area of a triangle: \text{Area of a triangle} = \frac{1}{2} \times \text{base} \times \text{height}.

The area of triangle Ⅰ = the area of triangle Ⅱ = the area of triangle Ⅲ = the area of triangle Ⅳ.

The area of the shaded part is calculated as: \left( \frac{4 \times 4} {2} \right)\div 2 \times 2 = 8cm^{2}

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Problem 2 AMC 8 Daily Practice - Area Tricks
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