AMC 10 Daily Practice Round 1

Complete problem set with solutions and individual problem pages

Problem 2 Medium

A hiking group consists of 6 men and 9 women. The average age of the men is 57 years, and the average age of the women is 52 years. What is the average age of all the members of the group?

  • A.

    54

  • B.

    54.4

  • C.

    55

  • D.

    55.2

  • E.

    56

Answer:A

To find the average age of all members of the group, we calculate the total age for both the men and the women.

The total age of the 6 men is: 6 \times 57 = 342 \text{ years}.

The total age of the 9 women is: 9 \times 52 = 468 \text{ years}.

The total age of the group is: 342 + 468 = 810 \text{ years}.

The total number of people in the group is: 6 + 9 = 15.

Therefore, the average age of all members is: \frac{810}{15} = 54 \text{ years}.

Thus, the average age of the group is \boxed{54}.

Related Problems
Problem 1 AMC 10 Daily Practice Round 1
Problem 3 AMC 10 Daily Practice Round 1
Problem 4 AMC 10 Daily Practice Round 1
Problem 5 AMC 10 Daily Practice Round 1
Think Academy Powered by ChatGPT