2025 AMC 8

Complete problem set with solutions and individual problem pages

Problem 6 Easy

Sekou writes the numbers 15, 16, 17, 18, 19. After he erases one of his numbers, the sum of the remaining four numbers is a multiple of 4. Which number did he erase?

  • A.

    15

  • B.

    16

  • C.

    17

  • D.

    18

  • E.

    19

Answer:C

Solution 1

The sum of all five numbers is 85. Since 85 is 1 more than a multiple of 4, the number being subtracted must be 1 more than a multiple of 4. Thus, the answer is \boxed{\textbf{(C)}~17}.

 

Solution 2

The sum of the residues of these numbers modulo 4 is -1+0+1+2+3=5 \equiv 1 \pmod 4. Hence, the number being subtracted must be congruent to 1 modulo 4. The only such answer is \boxed{\textbf{(C)}~17}.