AMC 10 Weekly Practice Round 3

Complete problem set with solutions and individual problem pages

Problem 4 Easy

From 1,2,3,4,5, and 6, select any three different digits to form a three-digit number. Among all such numbers, how many odd numbers that greater than 300 can be formed?

  • A.

    32

  • B.

    40

  • C.

    56

  • D.

    60

  • E.

    68

Answer:B

Two cases:

If the hundreds digit is 3 or 5, then there are

2 \times 2 \times 4 = 16

odd three-digit numbers.

If the hundreds digit is 4 or 6, then there are

2 \times 3 \times 4 = 24

odd three-digit numbers.

 

Therefore, the total number of odd three-digit numbers satisfying the condition is 16 + 24 = 40.

Related Problems
Problem 2 AMC 10 Weekly Practice Round 3
Problem 3 AMC 10 Weekly Practice Round 3
Problem 5 AMC 10 Weekly Practice Round 3
Problem 6 AMC 10 Weekly Practice Round 3
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