2020 AMC 10 A

The ones digit, for all numbers divisible by , must be either or . However, from the restriction in the problem, it must be even, giving us exactly one choice (0) for this digit. For the middle two digits, we may choose any even integer from , meaning that we have total options. For the first digit, we follow similar intuition but realize that it cannot be , hence giving us possibilities. Therefore, using the multiplication rule, we get .