2024 AMC 8

Complete problem set with solutions and individual problem pages

Problem 9 Easy

All the marbles in Maria's collection are red, green, or blue. Maria has half as many red marbles as green marbles, and twice as many blue marbles as green marbles. Which of the following could be the total number of marbles in Maria's collection?

  • A.

    24

  • B.

    25

  • C.

    26

  • D.

    27

  • E.

    28

Answer:E

Solution 1

Since she has half as many red marbles as green, we can call the number of red marbles x, and the number of green marbles 2x. Since she has half as many green marbles as blue, we can call the number of blue marbles 4x. Adding them up, we have: 7x marbles. The number of marbles therefore must be a multiple of 7, as x represents an integer, so the only possible answer is \boxed{\textbf{(E) 28}}.

 

Solution 2

Suppose Maria has g green marbles and t total marbles. She then has \frac{g}{2} red marbles and 2g blue marbles. Altogether, Maria has

g + \frac{g}{2} + 2g = \frac{7g}{2} = t

marbles, so g = \dfrac{2t}{7}, so t must be a multiple of 7. The only multiple of 7 in the answer choices is \boxed{\textbf{(E) 28}}.