AMC 8 Daily Practice Round 1

Complete problem set with solutions and individual problem pages

Problem 25 Hard

Using the digits 1, 2, 3, 4, 5 to form a five-digit number (each digit used at most once), such that the difference between any two adjacent digits is at least 2. How many such five-digit numbers are there?

  • A.

    10

  • B.

    12

  • C.

    14

  • D.

    16

  • E.

    18

Answer:C

Starting with 1: 2 numbers — 13524, 14253;

so starting with 5, there are also 2 numbers.

Starting with 2: 3 numbers — 24135, 24153, 25314;

so starting with 4, there are also 3 numbers.

Starting with 3: 4 numbers — 31425, 31524, 35241, 35142.

Starting with 4: 3 numbers — 41352, 42513, 42531.

Starting with 5: 2 numbers — 52413, 53142.

Therefore, the total number of such five-digit numbers is 14.