AMC 8 Daily Practice Round 11

Complete problem set with solutions and individual problem pages

Problem 8 Easy

Three cards with the numbers 4, 5, and 6 are available. If these three cards are randomly arranged to form a three-digit number, what is the probability that the resulting number is a multiple of 5?

  • A.

    \frac{1}{6}

  • B.

    \frac{1}{4}

  • C.

    \frac{1}{3}

  • D.

    \frac{1}{2}

  • E.

    \frac{2}{3}

Answer:C

To solve the problem, we first list all possible three-digit numbers that can be formed using the digits 4, 5, and 6: 456, 465, 546, 564, 654, 645. There are 6 such numbers in total. A number is a multiple of 5 if its last digit is 5. From the list, 465 and 645 meet this condition, so there are 2 favorable outcomes. Using the probability formula, the probability of forming a number that is a multiple of 5 is:

\frac{2}{6} = \frac{1}{3}.