2020 AMC 8

Complete problem set with solutions and individual problem pages

Problem 24 Hard

A large square region is paved with n^2 gray square tiles, each measuring s inches on a side. A border d inches wide surrounds each tile. The figure below shows the case for n=3. When n=24, the 576 gray tiles cover 64\% of the area of the large square region. What is the ratio \frac{d}{s} for this larger value of n?

  • A.

    \frac{6}{25}

  • B.

    \frac{1}{4}

  • C.

    \frac{9}{25}

  • D.

    \frac{7}{16}

  • E.

    \frac{9}{16}

Answer:A

Solution 1

The area of the shaded region is (24s)^2. To find the area of the large square, we note that there is a d-inch border between each of the 23 pairs of consecutive squares, as well as from between the first/last squares and the large square, for a total of 23+2 = 25 times the length of the border, i.e. 25d. Adding this to the total length of the consecutive squares, which is 24s, the side length of the large square is (24s+25d), yielding the equation \frac{(24s)^2}{(24s+25d)^2}=\frac{64}{100}. Taking the square root of both sides (and using the fact that lengths are non-negative) gives \frac{24s}{24s+25d}=\frac{8}{10} = \frac{4}{5}, and cross-multiplying now gives 120s = 96s + 100d \Rightarrow 24s = 100d \Rightarrow \frac{d}{s} = \frac{24}{100} = \boxed{\textbf{(A) }\frac{6}{25}}.

 

Solution 2

WLOG (Without Loss of Generality), we may let s=1 (since d will be determined by the scale of s, and we are only interested in the ratio \frac{d}{s}). Then, as the total area of the 576 gray tiles is simply 576, the large square has area \frac{576}{0.64} = 900, making the side of the large square \sqrt{900}=30. As in Solution 1, the side length of the large square consists of the total length of the gray tiles and 25 lots of the border, so the length of the border is d = \frac{30-24}{25} = \frac{6}{25}. Since \frac{d}{s}=d if s=1, the answer is \boxed{\textbf{(A) }\frac{6}{25}}.