AMC 10 Daily Practice - Similarity

Complete problem set with solutions and individual problem pages

Problem 1 Easy

In the figure, DE{//}BC. If BD=12, AD=2, AE=3, then AC=            .

  • A.

    6

  • B.

    12

  • C.

    9

  • D.

    15

  • E.

    18

Answer:D

∵BD=12，AD=2,

∴AB=BD-AD=12-2=10,

∵BC{//}DE,

∴\triangle BCA\mathbf{\backsim }\triangle DEA,

∴\frac{AC}{AE}=\frac{BA}{DA},

∵AE=3，AB=10，AD=2,

∴\frac{AC}{3}=\frac{10}{2},

∴AC=15

Related Problems
Problem 2 AMC 10 Daily Practice - Similarity
Problem 3 AMC 10 Daily Practice - Similarity
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