2015 AMC 8

Complete problem set with solutions and individual problem pages

Problem 24 Hard

A baseball league consists of two four-team divisions. Each team plays every other team in its division N games. Each team plays every team in the other division M games with N>2M and M>4. Each team plays a 76 game schedule. How many games does a team play within its own division?

  • A.

    36

  • B.

    48

  • C.

    54

  • D.

    60

  • E.

    72

Answer:B

Solution 1

On one team they play 3N games in their division and 4M games in the other. This gives 3N+4M=76.

Since M>4 we start by trying M=5. This doesn't work because 56 is not divisible by 3.

Next, M=6 does not work because 52 is not divisible by 3.

We try M=7 does work by giving N=16 ,~M=7 and thus 3\times 16=\boxed{\textbf{(B)}~48} games in their division.

M=10 seems to work, until we realize this gives N=12, but N>2M so this will not work.

 

Solution 2

76=3N+4M > 10M, giving M \leqslant 7. Since M>4, we have M=5,6,7. Since 4M is 1 \pmod{3}, we must have M equal to 1 \pmod{3}, so M=7.

This gives 3N=48, as desired. The answer is \boxed{\textbf{(B)}~48}.