2024 AMC 8

Complete problem set with solutions and individual problem pages

Problem 21 Hard

A group of frogs (called an army) is living in a tree. A frog turns green when in the shade and turns yellow when in the sun. Initially, the ratio of green to yellow frogs was 3 : 1. Then 3 green frogs moved to the sunny side and 5 yellow frogs moved to the shady side. Now the ratio is 4 : 1. What is the difference between the number of green frogs and the number of yellow frogs now?

  • A.

    10

  • B.

    12

  • C.

    16

  • D.

    20

  • E.

    24

Answer:E

Solution 1

Let the initial number of green frogs be g and the initial number of yellow frogs be y. Since the ratio of the number of green frogs to yellow frogs is initially 3 : 1, g = 3y. Now, 3 green frogs move to the sunny side and 5 yellow frogs move to the shade side, thus the new number of green frogs is g + 2 and the new number of yellow frogs is y - 2. We are given that \frac{g + 2}{y - 2} = \frac{4}{1}, so g + 2 = 4y - 8, since g = 3y, we have 3y + 2 = 4y - 8, so y = 10 and g = 30. Thus the answer is (g + 2) - (y - 2) = 32 - 8 = \boxed{(E) \hspace{1 mm} 24}.

 

Solution 2

Since the original ratio is 3:1 and the new ratio is 4:1, the number of frogs must be a multiple of 12, the only solutions left are (B) and (E).

Let's start with 12 frogs:

We must have 9 frogs in the shade and 3 frogs in the sun. After the change, there would be 11 frogs in the shade and 1 frog in the sun, which is not a 4:1 ratio.

Therefore the answer is: \boxed{(E) \hspace{1 mm} 24}.