2025 AMC 8

Complete problem set with solutions and individual problem pages

Problem 16 Hard

Five distinct integers from 1 to 10 are chosen, and five distinct integers from 11 to 20 are chosen. No two numbers differ by exactly 10. What is the sum of the ten chosen numbers?

  • A.

    95

  • B.

    100

  • C.

    105

  • D.

    110

  • E.

    115

Answer:C

Solution 1

Note that for no two numbers to differ by 10, every number chosen must have a different units digit. To make computations easier, we can choose (1, 2, 3, 4, 5) from the first group and (16, 17, 18, 19, 20) from the second group. Then the sum evaluates to 1+2+3+4+5+16+17+18+19+20 = \boxed{\text{(C) 105}}.

 

Solution 2

For 1+2+3+4+5+16+17+18+19+20, we can add the first term and the last term, which is 21. If we add the second term and the second-to-last term it is also 21. There are 5 pairs that sum to 21, so the answer is 21 \times 5 which equals \boxed{\text{(C) 105}}.