2020 AMC 10 A

Complete problem set with solutions and individual problem pages

Problem 8 Easy

What is the value of 1+2+3-4+5+6+7-8+\cdots+197+198+199-200?

  • A.

    9,800

  • B.

    9,900

  • C.

    10,000

  • D.

    10,100

  • E.

    10,200

Answer:B

Solution 1: Split the even numbers and the odd numbers apart. If we group every 2 even numbers together and add them, we get a total of 50 \cdot(-2)=-100. Summing the odd numbers is equivalent to summing the first 100 odd numbers, which is equal to 100^{2}=10000. Adding these two, we obtain the answer of (B) 9900

Solution 2 (bashy): We can break this entire sum down into 4 integer bits, in which the sum is 2 x, where x is the first integer in this bit. We can find that the first sum of every sequence is 4 x-3, which we plug in for the 50 bits in the entire sequence is 1+2+3+\cdots+50=1275, so then we can plug it into the first term of every sequence equation we got above 4(1275)-3(50)=4950, and so the sum of every bit is 2 x, and we only found the value of X, the sum of the sequence \text { is } 4950 \cdot 2=(B) 9900