AMC 8 Daily Practice - Calculation Tricks by Grouping

Complete problem set with solutions and individual problem pages

Problem 6 Medium

What is the value of 2+4-6+8+10-12+ \dots+92+94-96+98?

  • A.

    720

  • B.

    818

  • C.

    863

  • D.

    800

  • E.

    0

Answer:B

This problem is somewhat unique and requires careful observation. We notice that the operation signs repeat every three numbers in the pattern ++-.

Therefore, we can group every three numbers together. The sum of the first group is 0, the sum of the second group is 6, and the sum of the third group is 12, indicating that these sums form an arithmetic sequence with a common difference of 6.

Calculating the number of groups: 98 \div 2 = 49 terms, then 49 \div 3 = 16 groups with a remainder of 1 term. Thus, there are 16 complete groups.

We can rewrite the original expression as: 2 + 4 - 6 + 8 + 10 - 12 + \dots + 92 + 94 - 96 + 98 = (2 + 4 - 6) + (8 + 10 - 12) + \dots + (92 + 94 - 96) + 98 = 0 + 6 + 12 + \dots + 90 + 98

This forms an arithmetic sequence with: - First term a_1 = 0 - Common difference d = 6 - Last term a_{16} = 90 -

Applying the arithmetic series sum formula (Gauss's formula): S_n = \frac{n(a_1 + a_n)}{2} + \text{remaining term} S = \frac{16 \times (0 + 90)}{2} + 98 = 720 + 98 = 818

The final result is \boxed{818}.