AMC 8 Daily Practice Round 2

Complete problem set with solutions and individual problem pages

Problem 5 Easy

The thousands digit of a four-digit number is 4 less than the ones digit. Then reverse all the digits of the four-digit number to get a new number. Then we subtract the original number from the new four-digit number. What is the ones digit of the result after subtraction?

  • A.

    3

  • B.

    4

  • C.

    5

  • D.

    6

  • E.

    7

Answer:D

Method1: Let the thousands, hundreds, tens, and ones digits of the original four-digit number be a, b, c, and d respectively. We are given that a=d-4. The original four-digit number is equal to 1000a+100b+10c+d=1001d+100b+10c-4000. The thousands, hundreds, tens and ones digits of the reversed four-digit number are d, c, b, and a, respectively. This number is equal to 1000d+100c+10b+a=1001d+100c+10b-4. Subtracting the original expression from the new one, we get\left( 1001d+100b+10c-4000 \right)-\left( 1001d+100c+10b-4 \right)=90c-90b+3996. Thus, the ones digit in the final result is 6.

Method2:The result must hold for any four-digit number with thousands digit being 4 less than the ones digit. 1025 is such a number. Evaluating we get 5201-1025=4176. Thus, the ones digit in the final result is 6.