AMC 8 Daily Practice Round 11

Complete problem set with solutions and individual problem pages

Problem 24 Easy

There are 6 students, and no two students own the same set of books. However, each pair of students shares exactly one common book, and each book is owned by exactly two students. How many different books are there in total?

  • A.

    12

  • B.

    15

  • C.

    18

  • D.

    21

  • E.

    24

Answer:B

Represent the 6 students as points A_1, A_2, A_3, A_4, A_5, A_6, and use a line connecting two points to indicate that the corresponding pair of students shares exactly one common book. Since each book is owned by exactly two students, there is exactly one line between any two points.

To find the total number of books, we count the total number of lines in a complete graph with 6 points. The number of lines (or edges) in a complete graph with n points is given by:

\binom{n}{2} = \frac{n(n-1)}{2}.

For n = 6, the total number of lines is:

\binom{6}{2} = \frac{6 \times 5}{2} = 15.

Thus, the 6 students share a total of 15 different books. The answer is \boxed{15}.