AMC 10 Daily Practice - Polygons

Complete problem set with solutions and individual problem pages

Problem 1 Easy

As shown in the diagram, the side AM of the square AMNP lies on the side AB of the regular pentagon ABCDE, what is the measure of \angle PAE?

  • A.

    15^\circ

  • B.

    16^\circ

  • C.

    17^\circ

  • D.

    18^\circ

  • E.

    19^\circ

Answer:D

\because quadrilateral A M N P is a square, pentagon A B C D E is regular, \therefore \angle E A B=\frac{(5-2) \times 180^{\circ}}{5}=108^{\circ}, \angle P A B=90^{\circ},

\therefore \angle P A E=\angle E A B-\angle P A B=18^{\circ}, si the answer is 18^\circ.

Related Problems
Problem 2 AMC 10 Daily Practice - Polygons
Problem 3 AMC 10 Daily Practice - Polygons
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