AMC 8 Daily Practice - Perimeter Tricks

Complete problem set with solutions and individual problem pages

Problem 2 Easy

Seven identical rectangles, each with a length of 5 cm and a width of 2 cm, are arranged as shown in the figure below. What is the perimeter of this figure in centimeters?

  • A.

    82

  • B.

    86

  • C.

    90

  • D.

    94

  • E.

    98

Answer:B

As shown in the figure, the perimeter of the combined figure can be calculated using the formula: \text{Perimeter} = 7 \times \text{(Perimeter of one rectangle)} - 6 \times \text{(Width of one rectangle)}.

Given that the length l = 5cm and width w = 2cm, the perimeter of one rectangle is 2 \times (5 + 2) = 14cm.

Substituting these values into the formula: \text{Perimeter} = 7 \times 14 - 6 \times 2 = 98 - 12 = 86 cm.

Thus, the perimeter of the figure is \boxed{86}cm.

Related Problems
Problem 1 AMC 8 Daily Practice - Perimeter Tricks
Problem 3 AMC 8 Daily Practice - Perimeter Tricks
Problem 4 AMC 8 Daily Practice - Perimeter Tricks
Problem 5 AMC 8 Daily Practice - Perimeter Tricks
Think Academy Powered by ChatGPT