2023 AMC 8

Complete problem set with solutions and individual problem pages

Problem 12 Medium

The figure below shows a large white circle with a number of smaller white and shaded circles in its interior. What fraction of the interior of the large white circle is shaded?

  • A.

    \frac{1}{4}

  • B.

    \frac{11}{36}

  • C.

    \frac{1}{3}

  • D.

    \frac{19}{36}

  • E.

    \frac{5}{9}

Answer:B

Solution 1

First, the total area of the radius 3 circle is simply just 9\cdot \pi when using our area of a circle formula.

Now from here, we have to find our shaded area. This can be done by adding the areas of the \frac{1}{2}-radius circles and add; then, take the area of the 1 radius circles and subtract that from the area of the 2 radius circle to get our resulting complex shape area. Adding these up, we will get

3\cdot \frac{1}{4} \pi + 4 \pi -\pi - \pi = \frac{3}{4} \pi + 2 \pi = \frac{11\cdot \pi}{4}.

So, our answer is \frac {\frac{11}{4} \pi}{9 \pi} = \boxed{\textbf{(B)}\ \frac{11}{36}}.

 

Solution 2

Pretend each circle is a square. The large shaded circle is a square with area 16~\text{units}^2, and the two white circles inside it each have areas of 4~\text{units}^2, which adds up to 8~\text{units}^2. The three small shaded circles become three squares with area 1~\text{units}^2, and add up to 3~\text{units}^2. Adding the areas of the shaded circles (19) and subtracting the areas of the white circles (8), we get 11~\text{units}^2. Since the largest white circle in which all these other circles are becomes a square that has area 36~\text{units}^2, our answer is \boxed{\textbf{(B)}\ \dfrac{11}{36}}.