2014 AMC 8

Complete problem set with solutions and individual problem pages

Problem 24 Hard

One day the Beverage Barn sold 252 cans of soda to 100 customers, and every customer bought at least one can of soda. What is the maximum possible median number of cans of soda bought per customer on that day?

  • A.

    2.5

  • B.

    3.0

  • C.

    3.5

  • D.

    4.0

  • E.

    4.5

Answer:C

In order to maximize the median, we need to make the first half of the numbers as small as possible. Since there are 100 people, the median will be the average of the 50\text{th} and 51\text{st} largest amount of cans per person. To minimize the first 49, they would each have one can. Subtracting these 49 cans from the 252 cans gives us 203 cans left to divide among 51 people. Taking \frac{203}{51} gives us 3 and a remainder of 50. Seeing this, the largest number of cans the 50th person could have is 3, which leaves 4 to the rest of the people. The average of 3 and 4 is 3.5. Thus our answer is \boxed{\text{(C) }3.5}.