2021 AMC 10 A Fall

Complete problem set with solutions and individual problem pages

Problem 17 Hard

An architect is building a structure that will place vertical pillars at the vertices of regular hexagon A B C D E F, which is lying horizontally on the ground. The six pillars will hold up a flat solar panel that will not be parallel to the ground. The heights of pillars at A, B, and C are 12,9 , and 10 meters, respectively. What is the height, in meters, of the pillar at E ?(2021 AMC Fall 10A, Question #17)

  • A.

    9

  • B.

    6 \sqrt{3}

  • C.

    8 \sqrt{3}

  • D.

    17

  • E.

    12 \sqrt{3}

Answer:D

Solution 1:

The pillar at B has height 9 and the pillar at A has height 12 . Since the solar panel is flat, the inclination from pillar B to pillar A is 3 . Call the center of the hexagon G. Since \overrightarrow{C G} \| \overrightarrow{B A}, it follows that the solar panel has height 13 at G. Since the solar panel is flat, the heights of the solar panel at B, G, and E are collinear. Therefore, the pillar at E has height 9+4+4=\text { (D) } 17 \text {. }

Solution 2:

Let the height of the pillar at D be x. Notice that the difference between the heights of pillar C and pillar D is equal to the difference between the heights of pillar A and pillar F. So, the height at F is x+2. Now, doing the same thing for pillar E we get the height is x+3. Therefore, we can see the difference between the heights at pillar C and pillar D is half the difference between the heights at B and E, so \begin{aligned} x+3-9 &=2 \cdot(x-10) \\ x-6 &=2 \cdot(x-10) \\ x &=14 \end{aligned} The answer is x+3= (D) 17 .