2022 AMC 8

Complete problem set with solutions and individual problem pages

Problem 18 Hard

The midpoints of the four sides of a rectangle are (-3,0), (2,0), (5,4), and (0,4). What is the area of the rectangle?

  • A.

    20

  • B.

    25

  • C.

    40

  • D.

    50

  • E.

    80

Answer:C

Solution 1

The midpoints of the four sides of every rectangle are the vertices of a rhombus whose area is half the area of the rectangle: Note that the diagonals of the rhombus have the same lengths as the sides of the rectangle.

Let A=(-3,0), B=(2,0), C=(5,4), and D=(0,4). Note that A,B,C, and D are the vertices of a rhombus whose diagonals have lengths AC=4\sqrt{5} and BD=2\sqrt{5}. It follows that the dimensions of the rectangle are 4\sqrt{5} and 2\sqrt{5}, so the area of the rectangle is 4\sqrt{5}\cdot2\sqrt{5}=\boxed{\textbf{(C) } 40}.

 

Solution 2

If a rectangle has area K, then the area of the quadrilateral formed by its midpoints is \frac{K}{2}.

Define points A,B,C, and D as Solution 1 does. Since A,B,C, and D are the midpoints of the rectangle, the rectangle's area is 2[ABCD]. Now, note that ABCD is a parallelogram since AB=CD and \overline{AB}\parallel\overline{CD}. As the parallelogram's height from D to \overline{AB} is 4 and AB=5, its area is 4\cdot5=20. Therefore, the area of the rectangle is 20\cdot2=\boxed{\textbf{(C) } 40}.