AMC 10 Weekly Practice Round 2

Complete problem set with solutions and individual problem pages

Problem 20 Hard

On a circular track, 2015 flags are placed at equal intervals. Person A and person B start at the same time from the same flag, running in the same direction. When they both return to the starting point together again, A has run 23 laps and B has run 13 laps. Excluding the starting flag position, how many times does A overtake B exactly at a flag position?

  • A.

    1

  • B.

    2

  • C.

    3

  • D.

    4

  • E.

    5

Answer:D

Let the distance between two adjacent flags be 1, so the circumference of the track is 2015.

Since v_A : v_B = 23 : 13, let v_A = 23x and v_B = 13x.

For A to overtake B, A must run n more laps than B.

Then:

(23x - 13x)t = 2015n

10x \cdot t = 2015n

Thus, the time taken for A to overtake B is: t = \frac{403n}{2x}.

In this time, A covers a distance of: 23x \times \frac{403n}{2x} = \frac{23 \times 403}{2}n.

For A to overtake B exactly at a flag position, the distance covered must be an integer, which requires n to be even.

Thus: n = 2, 4, 6, 8, 10 (the maximum is 10 extra laps).

However, when n = 10, both runners return to the starting point.

Therefore, A overtakes B exactly at a flag position 4 times.