2020 AMC 10 A

Complete problem set with solutions and individual problem pages

Problem 1 Easy

What value of x satisfies x-\frac{3}{4}=\frac{5}{12}-\frac{1}{3}?

  • A.

    -\frac{2}{3}

  • B.

    \frac{7}{36}

  • C.

    \frac{7}{12}

  • D.

    \frac{2}{3}

  • E.

    \frac{5}{6}

Answer:E

Adding \frac{3}{4} to both sides, x=\frac{5}{12}-\frac{1}{3}+\frac{3}{4}=\frac{5}{12}-\frac{4}{12}+\frac{9}{12}=(\text{E}) \frac{5}{6}.

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