2018 AMC 8

Complete problem set with solutions and individual problem pages

Problem 12 Medium

The clock in Sri's car, which is not accurate, gains time at a constant rate. One day as he begins shopping, he notes that his car clock and his watch (which is accurate) both say 12:00 noon. When he is done shopping, his watch says 12:30 and his car clock says 12:35. Later that day, Sri loses his watch. He looks at his car clock and it says 7:00. What is the actual time?

  • A.

    5:50

  • B.

    6:00

  • C.

    6:30

  • D.

    6:55

  • E.

    8:10

Answer:B

Solution 1

We see that every 35 minutes the clock passes, the watch passes 30 minutes. That means that the clock is \frac{7}{6} as fast the watch, so we can set up proportions. \dfrac{\text{car clock}}{\text{watch}}=\dfrac{7}{6}=\dfrac{7 \text{ hours}}{x \text{ hours}}. Cross-multiplying we get x=6. Now, this is obviously redundant, because we could just eyeball it to see that the watch would have passed 6 hours. But this method is better when the numbers are a bit more complex, which makes it both easier and reliable. Either way, our answer is \boxed{\textbf{(B) }6:00}.

 

Solution 2

The ratio of the car clock to the watch clock is a ratio of 35:30 or 7:6 due to the clock being ahead by 5 minutes after 30 minutes has passed. This means that when the car clock passes 7 hours, the watch has passed 6 hours, meaning that the time would be \boxed{\textbf{(B) }6:00}.