2016 Math Kangaroo Real Questions and Analysis

In this article, you’ll find:

  • A topic distribution chart for the 2016 Math Kangaroo Levels 1–4
  • Key concepts tested in each topic
  • A question–module mapping table
  • Several real 2016 questions with solutions and common mistakes
  • Study tips and resources to prepare effectively for Math Kangaroo

2016 Math Kangaroo Overview

The Math Kangaroo competition consists of a single 75-minute multiple-choice test with five answer options per question. Students can participate either online or on paper.

Scoring Structure

  • Grades 1–4: 24 questions, maximum score of 96 points
  • Grades 5–12: 30 questions, maximum score of 120 points

Learn more about Math Kangaroo Format and Scoring Here: Math Kangaroo FAQ and Resources: Your Ultimate Guide

Levels 1-2 Analysis

Topic Distribution

The 2016 Math Kangaroo Levels 1–2 exam emphasizes spatial and visual thinking (29%) as well as logical reasoning (29%), while also testing basic number sense (25%) and everyday word problems (17%).

2016 Math KangarooLevels1-2 Question Breakdown by Module

Detailed Module Summary

ModuleQuestion NumbersWhat It Tests (Brief)
GeometryQ5, Q8, Q17, Q18, Q19, Q21, Q23Maze; building and counting blocks; puzzles; squares, arranging and dividing shapes; opposite faces 
ReasoningQ2, Q9, Q10, Q13, Q15, Q20, Q22Visual tracking; positional reasoning; rule-based logic; matching reasoning; sum–difference logic
Word ProblemQ4, Q11, Q14, Q16Basic addition & subtraction word problems; age and month problems; sum–difference problems
NumberQ1, Q3, Q6, Q7, Q12, Q24Counting; subtraction; grouping numbers

Real Questions and Solutions Explained

Geometry Example – Problem 17

Question:

2026Mklv1-2 Geometry Example - Problem 17

Solution:

Only (E) cannot be made from “T” shapes.

2016Mklv1-2 Geometry Example - Problem 17 solution

Answer: E

Common Mistakes:

  • Thinking that shapes just need to match in size, not structure.
  • Forgetting to rotate the “T” shape to test different fits.

Reasoning Example – Problem 20

Question:

Five sparrows sat on a wire as shown in the picture. Each sparrow chirped only once to each bird it saw on the side it faced. For example, the second sparrow chirped one time. In total, how many times did they chirp?

2016Mklv1-2 Reasoning Example - Problem 20

(A) 6 (B) 8 (C) 9 (D) 10 (E) 12

Solution:

Look at each sparrow and count how many birds it can see (in the direction it’s facing):

  • The first sparrow (red) looks right → sees 4 birds → chirps 4 times
  • The second sparrow (blue) looks left → sees 1 bird → chirps 1 time
  • The third sparrow (green) looks right → sees 2 birds → chirps 2 times
  • The fourth sparrow (purple) looks left → sees 3 birds → chirps 3 times
  • The fifth sparrow looks right → sees no one → chirps 0 times

Add them up: 4 + 1 + 2 + 3 + 0 = 10

2016Mklv1-2 Reasoning Example - Problem 20 solution

Answer: D

Common Mistakes:

  • Forgetting which way the birds are facing and counting all the birds, not just the ones seen.
  • Double-counting chirps or skipping a bird.

Word Problem Example – Problem 4

Question:

In a cave, there were only two seahorses, one starfish, and three turtles. Later, five seahorses, three starfish, and four turtles joined them. How many sea animals gathered in the cave?

(A) 6 (B) 9 (C) 12 (D) 15 (E) 18

Solution:

First, count the animals already in the cave: 2 + 1 + 3 = 6 animals. Next, count the animals that joined: 5 + 3 + 4 = 12 animals. Last, add both groups together: 6 + 12 = 18 animals.

Answer: E

Common Mistakes:

  • Forgetting to add the animals that joined later

Number Example – Problem 6

Question:

Ten friends came to John’s birthday party. Six of them were girls. How many boys were at the party?

(A) 4 (B) 5 (C) 6 (D) 7 (E) 8

Solution:

John had 10 friends at the party, and 6 of them were girls. That means 4 of the friends were boys: 10 − 6 = 4. But the question asks for how many boys were at the party, and John himself is a boy and is also at the party. So total boys = 4 boy friends + John = 5 boys.

Answer: B

Common Mistakes:

  • Forgetting to include John in the total count
  • Misreading the question as asking only about John’s friends, not the total boys present

Levels 3-4 Analysis

Topic Distribution

The 2016 Math Kangaroo Levels 3–4 exam places balanced emphasis on geometry (33%) and reasoning (25%), while also incorporating number problems (21%) and word problems (21%) to test well-rounded mathematical thinking.

2016 Math Kangaroo Levels3-4 Question Breakdown by Module

Detailed Module Summary

ModuleQuestion NumbersWhat It Tests (Brief)
GeometryQ4, Q5, Q7, Q8, Q12, Q13, Q14, Q17Symmetry and mirror reflection; identifying 2D shapes; puzzles; direction & positions; forming shapes; rotations
ReasoningQ10, Q15, Q16, Q21, Q23, Q24Reasoning with positions; logic rules; adjacency reasoning; equivalent substitution reasoning; patterns; rule-based logic
Word ProblemQ2, Q6, Q18, Q19, Q20Time problems; half word problems; age problems; multiples problems
NumberQ1, Q3, Q9, Q11, Q22Counting & comparing; addition & subtraction; digits; sums

Real Questions and Solutions Explained

Geometry Example – Problem 8

Question:

Which one of the following sentences correctly describes the picture on the left?

2016Mklv3-4 Geometry Example - Problem 8

(A) There are as many circles as squares.

(B) There are fewer circles than triangles.

(C) There are twice as many circles as triangles.

(D) There are more squares than triangles.

(E) There are two triangles more than circles.

Solution:

First, count each shape in the picture: Circles: 4; Squares: 2; Triangles: 2. So the correct description is that there are twice as many circles as triangles.

Answer: C

Common Mistakes:

  • Mixing up circles and squares
  • Not checking all options carefully

Reasoning Example – Problem 21

Question:

Karin wants to place five bowls on a table in order of their weight. She already placed bowls Q, R, S, and T in order. Bowl T weighs the most. Where must she place bowl Z?

2016MK lv3-4 Reasoning Example - Problem 21

(A) to the left of bowl Q (B) between bowl Q and bowl R 

(C) between bowl R and bowl S (D) between bowl S and bowl T (E) to the right of bowl T

Solution:

To find the correct position for bowl Z, compare the shapes inside each bowl:

Comparing Q and R: removing the same square from both shows that a triangle weighs less than a circle.

Now compare Z:

Bowl Z has one triangle, one circle, and one square — same as R.

Comparing Z and Q: both have a triangle and a square, but Z also has a circle, which makes Z heavier than Q.

Comparing Z and R: both have the same shapes, so Z weighs the same as R, but since the question asks for order, and R is already placed after Q, Z must be placed between Q and R.

Answer: B

Common Mistakes:

  • Forgetting to compare only the extra shapes when both bowls share common ones.

Word Problem Example – Problem 18

Question:

Tim, Tom, and Jim are triplets (three brothers born on the same day). Their brother Paul is exactly 3 years older. Which of the following numbers can be the sum of the ages of the four brothers?

(A) 25  (B) 27  (C) 29  (D) 30  (E) 60

Solution:

Paul is 3 years older than the triplets. So, if each triplet is the same age, let’s call that age X. Then the total age = X + X + X + (X + 3) = 4X + 3. We check which option gives a total that is 3 more than a multiple of 4. Only 27 works: 27 − 3 = 24, and 24 ÷ 4 = 6.

Answer: B

Common Mistakes:

  • Adding random numbers without checking the age difference.
  • Not checking if the remaining sum (after subtracting 3) is divisible by 4.

Number Example – Problem 11

Question:

Zoe has two cards. She wrote a number on each side of both cards. The sum of the two numbers on the first card is equal to the sum of the two numbers on the second card. The sum of the four numbers is 32. What could be the two numbers on the sides that we cannot see?

2016Mklv3-4 Number Example - Problem 11

(A) 7 and 0 (B) 8 and 1 (C) 11 and 4 (D) 9 and 2 (E) 6 and 3

Solution:

We are told the two cards have equal sums on each side, and the total of all four numbers is 32. If both card sums are equal, that means each card adds up to 16 (because 32 ÷ 2 = 16). We can see one side of each card: 5 and 12. So the hidden sides must be 16 − 5 = 11 and 16 − 12 = 4.

Answer: C

Common Mistakes:

  • Adding only the visible numbers without dividing total into two equal parts
  • Not subtracting from the correct total (32 ÷ 2 = 16 for each card)
  • Trying to guess without checking total sum logic

2016 Math Kangaroo Answer Key

QuestionLevel 1 & 2Level 3 & 4
1DE
2BE
3DA
4EA
5CD
6BB
7CA
8AC
9DB
10CB
11EC
12CB
13BD
14BA
15AC
16ED
17ED
18AB
19DD
20DC
21AB
22EC
23AE
24CB

Best Resources to Prepare for Math Kangaroo

Visit our All-in-One Math Kangaroo Hub for free and exclusive preparation materials, including video explanations, worksheets, and topic breakdowns.

 Math Kangaroo Resource Pack
Free Download: Levels 1–2 & 3–4
Past Exams (2023–2025) & 100-Question Practice Collection

You’ll find the download link in the confirmation message after submitting the form.

About Think Academy

Think Academy, wholly owned by TAL Education Group, specializes in preparing students for the Math Kangaroo competition. Each year, over 300 Think Academy students win Math Kangaroo awards, including 35% of all Level 1 perfect scores nationwide. 7 out of 10 Think participants won national awards in 2025. Supported by world-class resources and expert coaching, we empower students to achieve exceptional results in international mathematics competitions.

Want more insights on math education and parenting tips? Subscribe to our newsletter for weekly expert advice and updates on the latest learning tools.

Leave a Comment & Share Your Thoughts!

Published On: November 14, 2025
Think Academy Blog Evaluation Ad 2x
Subscribe to Our Newsletter

Join our mailing list for free math worksheets, educational trends, event updates, and more!

Share This Story, Choose Your Platform!

Related Posts