2025 AMC 8 Problem 24
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To help you master 2025 AMC 8 Problem 24, this page includes:
- The original AMC problem to try, plus the correct answer
- Clear, step-by-step solutions using different methods
- Key ideas, useful formulas, and takeaways you can apply to similar problems
- Related problems from past AMC exams, plus new practice problems that build the same skills
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2025 AMC8 Problem 24
24.
In trapezoid , angles and measure and . The side lengths are all positive integers, and the perimeter of is 30 units. How many non-congruent trapezoids satisfy all of these conditions?
Solution
Right Triangle Decomposition Method
By dropping altitudes from the top vertices, we can split the trapezoid into a rectangle and two right triangles. This allows us to express all four side lengths using just two variables.
In a right triangle, the side lengths are in the ratio . The leg opposite the angle is exactly half the length of the hypotenuse.
Step 1: Assign variables to the unknown sides
Let the length of the top base be represented by one variable, and let the lengths of the equal slanted sides be represented by another. Since the problem explicitly states that all side lengths are positive integers, both of these variables must be integers greater than or equal to 1.
Step 2: Draw altitudes to the base
Draw perpendicular lines from the top vertices down to the bottom base. Let the points where they intersect the bottom base be named and .
Step 3: Analyze the resulting right triangles
This geometric construction creates two right triangles on the outer edges of the trapezoid. Look at the right triangle on the left. We are given the base angle, and since the sum of angles in a triangle is always , the top angle must be . Using the properties of a triangle, the horizontal leg on the bottom is exactly half the length of the slanted hypotenuse. Because the trapezoid is symmetric, the right triangle on the other side has identical dimensions.
Step 4: Determine the length of the bottom base
The altitudes divide the trapezoid such that the middle section forms a rectangle. Therefore, the distance between the two altitudes along the bottom base is equal to the length of the top base. We can now express the entire bottom base as the sum of its three constituent parts.
Step 5: Set up the perimeter equation
Add the four side lengths of the trapezoid together to find its perimeter in terms of our variables. We set this sum equal to the given total perimeter.
Step 6: Solve for positive integer combinations
We must find positive integer solutions for this equation. Notice that the total perimeter and the term containing are both even numbers. For the equation to balance, the term containing must also be even, meaning itself must be an even integer. Let’s test consecutive even values for to find corresponding values for .
Step 7: Count the valid configurations
Each valid pair of and produces a trapezoid with a distinct set of side lengths. Because no two sets of side lengths are identical, these four trapezoids are strictly non-congruent. We stop at because a side length cannot be zero.
There are 4 valid non-congruent trapezoids, which corresponds to answer choice E. We can verify the side lengths for the first solution: if and , the sides are 12, 14, 2, and 2, which are positive integers that sum exactly to 30.
Parallelogram Decomposition Method
Drawing a line parallel to one of the slanted sides splits the trapezoid into a parallelogram and an equilateral triangle, instantly revealing the relationship between the top and bottom bases without using fractions.
An isosceles triangle containing one angle is always an equilateral triangle, meaning all three of its sides are equal.
Step 1: Assign variables to the unknown sides
As before, let the top base be represented by one variable and the equal slanted sides by another. We know these must be positive integers.
Step 2: Decompose the trapezoid
From the top-left vertex, draw a line down to the bottom base that is parallel to the right slanted side. Let this line intersect the bottom base at point .
Step 3: Identify the parallelogram
This drawn line cuts the trapezoid into two separate shapes. On the right, the top and bottom are parallel, and the left and right are parallel by our construction. This means it is a parallelogram. In any parallelogram, opposite sides are equal.
Step 4: Analyze the remaining triangle
Now look at the triangle on the left side. We see that two of its sides have length , meaning it is an isosceles triangle. Since the base angle is given as , the other two angles must also equal . This forces the triangle to be fully equilateral, so its third side along the base is also equal to .
Step 5: Find the perimeter equation
Combine the segments along the bottom base to find its total length. Then, calculate the total perimeter of the trapezoid by summing its four outer sides. We arrive at the exact same algebraic relationship as the previous method.
Step 6: Solve for valid integers
Equate this perimeter expression to . Because must be even, we test , producing four valid pairs of lengths.
We again find exactly 4 valid combinations. The bases are , , , and . Since each pair has a unique set of side lengths, they represent 4 non-congruent trapezoids, confirming choice E.
Similar Problems in Real Exams
The following five AMC 8 problems are closely related to AMC 8 2025 Question 24. These real AMC 8 problems test the same key concept—Quadrilaterals. Click any problem to learn and practice, then continue to the adapted practice section later in this article for more problems to try.
2025 AMC 8 Problem 18
2023 AMC 8 Problem 7
2017 AMC 8 Problem 11
2015 AMC 8 Problem 25
2011 AMC 8 Problem 13
Adapted Problems to Practice
What Formulas Do You Need for This Problem?
- 30-60-90 Right Triangle Properties:
In a right triangle with angles , , and , the side lengths are in the ratio .
The shortest leg is opposite the angle and is exactly half the length of the hypotenuse. Dropping an altitude from the top of an isosceles trapezoid with a base angle naturally creates a right triangle on the end.
- Parallelogram Opposite Sides:
If a quadrilateral is a parallelogram, then its opposite sides are equal in length.
Requires two pairs of parallel opposite sides. Drawing a line parallel to one leg of a trapezoid creates a parallelogram within the trapezoid, allowing lengths to be mapped from one side of the shape to another.
- Equilateral Triangle Identification:
If an isosceles triangle has at least one angle, then all three angles are and the triangle is fully equilateral.
Requires either two equal sides and the angle between them to be , or two equal sides and a base angle of . When the trapezoid is decomposed by a parallel line, the remaining shape is a triangle with two equal sides (length ) and a base angle of .
- Linear Diophantine Equations:
When an equation contains multiple variables but specifies that the solutions must be integers, you can use divisibility and parity (even/odd) properties to narrow down a finite list of possible answers.
Applies when variables are restricted to the set of integers (or positive integers). The problem asks for 'positive integer' side lengths, meaning the continuous equation can only be satisfied by a few specific discrete points.
Key Takeaway: Remember This Strategy for Next Time
When analyzing an isosceles trapezoid
Try: Try dropping altitudes from the top vertices to the bottom base.
Why: This perfectly splits the shape into a central rectangle and two identical right triangles on the edges, making it easy to calculate lengths and angles using standard triangle properties.
When an isosceles trapezoid has base angles
Try: Draw a line through one top vertex parallel to the opposite slanted leg.
Why: This highly efficient trick decomposes the trapezoid into a parallelogram and an equilateral triangle, immediately showing the relationship between the top and bottom bases without needing fractions or square roots.
When a geometry problem specifies that side lengths are 'positive integers'
Try: Express the given constraint (like perimeter or area) as an algebraic equation, then use parity (even/odd rules) to systematically test valid integer values.
Why: The integer constraint restricts the infinite possibilities of a continuous line down to a small, countable number of distinct solutions (a Diophantine equation).
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